Does the quantum spin of a particle relate to its frequency and wavelength? I cannot seem to find anything on this. If I were to guess, it seems that as $E = hf$, and $\omega = 2\pi f$, and $spin_1 = h/2\pi$, then $E/\omega = spin_1$.
Regards, Pete.
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Related : About de Broglie relations, what exactly is E ? Its energy of what?. – Frobenius Nov 15 '20 at 21:41
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No. A photon always has spin $1$ regardless of its wavelength, frequency or energy. An electron always has spin $\pm \frac 1 2$. You are confusing two different uses of the term frequency.
gandalf61
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1I seek to understand the wave/particle duality. If calculating the frequency of a particle from its quantum spin of h/2pi and the frequency of its wave from E = hf gives the same answer, then what two different uses of the term frequency have occurred? – Pete Carroll Nov 15 '20 at 17:13
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@PeteCarroll In $\omega=2 \pi f$, $\omega$ is angular velocity and $f$ is frequency of rotation. This frequency has nothing to do with the frequency of light, since a photon is not rotating (even though it has quantum spin). – gandalf61 Nov 15 '20 at 17:49