The solution of Schrodinger equation in finite square well gives discrete energies in the bound states, but the energy is not discrete in case of scattering state. What is the physical reason behind this?
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Qmechanic
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user157588
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2Possible duplicates: https://physics.stackexchange.com/q/39208/2451 , https://physics.stackexchange.com/q/65636/2451 , https://physics.stackexchange.com/q/68639/2451 and links therein. – Qmechanic Oct 19 '17 at 18:20
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What definition of scattering state do you use? – DanielC Oct 19 '17 at 19:16
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@DanielC for scattering state,a particle has energy more than the energy at infinity – user157588 Oct 20 '17 at 04:31