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I am a chemical/biological scientist by trade and wish to understand how quantum EM phenomena translates to our more recognizable classical world.

In particular, I want to get a mechanistic picture of what is going on when a tuned antenna is interacting with a photon of the desired frequency? I believe an individual electron on the antenna (many electrons) accepts a photon; but how does the eventual process of a measurable AC current build up on the dipole (or 1/4 wavelength, for example) to be fed with no reactance onto the transmission line?

"When photon meets antenna" is a great meeting ground for a quantum/classical bridge.

Unfortunately, I do not have a serious maths background, but will try anything suggested. I have read and listened to many of the Feynman's popular quantum discussions which only increases my thirst for a better understanding of how quantum EM translates to our more visible world.

Qmechanic
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7 Answers7

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Here is an experimentalist's view of the question:

1) one photon hits the antenna and raises a molecular electron band to a higher energy level, and it will fall back to its lower one, with the characteristic electromagnetic transition time of the order of 10^-16sec, giving the energy to the antenna grid of molecules. One photon will just disappear.

2)a stream of photons that carry a signal means: a) that there is enough amplitude, b) there is coherence between photons: photons carry spin and thus polarization and in order to carry a signal the phases between all photons must be fixed and be coherent in time and space. Coherent means that there are fixed phases in the whole bunch. When such a bunch of photons hits an antenna the coherence will be transferred to the individual photon absorptions and de-excitations by conservation of spin, building up a corresponding electromagnetic wave on the molecular Fermi conduction level which can be detected further as a signal.

3) It is simpler for such problems to use the classical EM picture.

anna v
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  • "The antenna grid molecules" I presume means the outer atoms on the antenna. 2. "there is enough amplitude" I presume means sufficient number of coherent photons to get to a detectable current. 3. I did not know that classical EM explains the first steps in photon electron interaction. I am trying to feel my way from photon interaction towards measurable current as described by classical EM. 4. I will need to read more about Fermi conduction and try to picture how measurable AC voltage and current builds. Have you any suggestions? Thanks again Anna.
  • – user6869 Dec 28 '11 at 08:46
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    As to point 3, what Anna may have meant is that there is really no reason to use quantum theory in practice because the EM waves that interact with antennas are large enough that quantum effects are completely negligible. – David Z Dec 28 '11 at 08:57
  • @DavidZaslavsky right David. Large enough in number of photons to act as an aggregate whose limiting behavior is the classical EM solutions. – anna v Dec 28 '11 at 12:17
  • @user6869 By grid I meant the crystal lattice, except an antenna is not an organized crystal but does have a structure. This is to contrast with energy levels on atoms and molecules which have much higher frequencies than the incoming RF. The collective modes of the solid state pick up the energy. Yes, amplitude means enough photons to carry the signal. Classical EM is the macroscopic statistical manifestation of the many photon state at the quantum level. – anna v Dec 28 '11 at 12:29
  • Have a look at http://motls.blogspot.com/2011/11/how-classical-fields-particles-emerge.html for a precis from Lubos who as a theorist is much more conversant than I. – anna v Dec 28 '11 at 12:30