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We consider that if the classical vacuua of a theory are degenerate then each of them can be non-invariant under one or more of the symmetries of the Lagrangian. We can choose one of the vacuua and construct our perturbative QFT around that vacuum. Via choosing a vacuum, we spontaneously break the symmetry and our perturbative QFT constructed around the chosen vacuum would have this (spontaneously) broken symmetry and not the original symmetry of the theory we started out with.

However, in principle, there would be instanton corrections to the classically obtained degenerate vacuua and the degeneracy would break and we would, in fact, have a true vacuum which would have the symmetry of the full theory. So, it seems that if we add the non-perturbative corrections, the spontaneously broken symmetry should be unbroken. However, this seems strange because this seems to suggest that non-perturbative corrections won't just change the results of perturbative calculations by tiny amounts but, rather, would qualitatively change predictions such as if the gauge boson should have mass or not. Or am I mixing non-perturbative and perturbative results in a naive incoherent way? If so, exactly how do we reconcile the two views? Or do we even need to?

  • That's why instantons are called non-perturbative corrections. You cannot treat them as small and do perturbation theory. – Kosm Jun 13 '19 at 16:37
  • @Kosm So, if I include instantons then my vacuum would be non-degenerate and the symmetry would remain unbroken? What I am confused about is the fact that since instanton corrections always remain smaller than perturbative corrections, I can't see how such small non-perturbative corrections would bring back the massive gauge boson of perturbative QFT to being massless in the non-perturbative theory. –  Jun 13 '19 at 16:51
  • that depends. Say, if you have axionic continuous shift symmetry and add instanton term for the axion, the continuous symmetry will be broken to a discrete one – Kosm Jun 13 '19 at 17:03
  • ... But the vacuum will still break that shift symmetry – Kosm Jun 13 '19 at 17:09
  • I see you are talking about gauged symmetry. Then instanton terms ($\sim aF\tilde{F}$, $a$ - axion) are not allowed by gauge symmetry unless it is anomalous. But if it is anomalous, you must add the instanton term to cancel the (cubic) anomaly by Green-Schwarz mechanism. Either way the massive vector boson will remain massive. Also keep in mind that gauge symmetry strictly speaking cannot be spontaneously broken since you can fix the gauge by hand, thus removing the symmetry. – Kosm Jun 14 '19 at 03:59
  • @Kosm Thank you for your comments. Can you suggest a reference where I can read up more about why it is not correct to say that a gauged symmetry is spontaneously broken? I am only familiar with SSB at the level of Ryder. In this introductory treatment, I don't remember coming across such a distinction between SSB of global symmetry and that of gauged symmetry. –  Jun 14 '19 at 11:39
  • google "Spontaneous symmetry breaking in the higgs mechanism". First pdf should do it. – Kosm Jun 14 '19 at 11:48
  • see also: https://physics.stackexchange.com/q/190416/85745 – Kosm Jun 14 '19 at 11:50
  • @DvijD.C. Do you find the answer? It is also my question. It is possible to have a true vacuum due to tunneling, and symmetry breaking might be an artifact of perturbation theory. – Arian Nov 14 '20 at 10:55
  • @Arian Sadly, no, I don't yet have a good understanding of the resolution of my question. Kindly write an answer to this post or link some other posts here if you find something relevant. –  Nov 14 '20 at 22:02
  • @DvijD.C. I found a link about the question.https://physics.stackexchange.com/questions/230731/are-there-instantonic-corrections-to-continuously-degenerate-vacua. I thought about two dimensional double well potential and I am convinced that it is true – Arian Apr 25 '21 at 15:50

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